Suppose now that you wanted to determine the density of a small crystal to confirm that it is graphite. From the literature, you know that graphite has a density of 2.25 g/cm^3. How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of CHCl3 (d = 1.492 g/mL) and CHBr3 (d = 2.890 g/mL)? (Note: 1 mL = 1 cm^3.)

The volume of first and second compound are 9.15 ml and 10.85 ml.

Explanation:

Given that,

Density of graphite = 2.25 g/cm³

Volume of mixture = 20.0 mL

Density of first compound = 1.492 g/ml

Density of second compound = 2.890 g/ml

Let the volume of first mixture = x

The volume of second mixture = (20-x)....(I)

We need to calculate the volume of first compound

Using formula of  density of mixture

Where, = volume of first compound

= volume of second compound

=density of first compound

= density of first compound

Put the volume into the formula

We need to calculate the volume of second compound

Using equation (I)

Put the value of x

Hence, The volume of first and second compound are 9.15 ml and 10.85 ml.

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2