Several systems and processes are described below. For each of them, determine whether the system is at steady state, at equilibrium, or neither. Determine also whether any of these adjectives are applicable to the system: isothermal, isobaric, isochoric, adiabatic, closed, or open. a. An ice cube that has just been dropped into a glass of warm water. b. An aluminum can full of soda that has been fully submerged in ice water for some time. c. The inside of a closed, perfectly insulated cooler that contains ice, water, and cans of soda. d. A closed, reasonably well insulated cooler that contains ice, water, and cans of soda. e. Your body, over the last 24 hours. f. Your body, over the last five years. g. The Atlantic Ocean, over the last 24 hours. h. The Atlantic Ocean, over the last million years.

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

the answer is a and have a great day

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole