A 25.0 mL sample of sulfuric acid is titrated with 30.0 mL of 0.150 M sodium hydroxide. Calculate the concentration of the sulfuric acid.

The concentration of the sulfuric acid is 0.09 M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

According to neutralization law,

where,

= basicity of sulphuric acid = 2

= Molarity of sulphuric acid solution = ?

= volume of sulphuric acid solution = 25.0 ml

= acidity of sodium hydroxide = 1

= Molarity of sodium hydroxide  = 0.150 M

= volume of sodium hydroxide = 30.0 ml

Thus  the concentration of the sulfuric acid is 0.09 M

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