A solution is prepared at that is initially in benzoic acid , a weak acid with , and in sodium benzoate . Calculate the pH of the solution. Round your answer to decimal places.

Two nitro no2 groups are chemically bonded to a patch of surface. they can't move to another location on the surface, but they can rotate (see sketch at right). it turns out that the amount of rotational kinetic energy each no2 group can have is required to be a multiple of ε, where =ε×1.010−24 j. in other words, each no2 group could have ε of rotational kinetic energy, or 2ε, or 3ε, and so forth — but it cannot have just any old amount of rotational kinetic energy. suppose the total rotational kinetic energy in this system is initially known to be 32ε. then, some heat is removed from the system, and the total rotational kinetic energy falls to 18ε. calculate the change in entropy. round your answer to 3 significant digits, and be sure it has the correct unit symbol.

Can someone me with 6 to 10 plz this is for masteries test.

20 look at the clock and the data table below. based on the data and on your knowledge of potential and kinetic energy, what is the best conclusion you can make about potential and kinetic energy? the total amount of energy stays the same. the clock has the most potential energy at point b since it is moving the fastest. there is always more potential energy than kinetic energy. potential energy can never be 0, but you can have 0 kinetic energy.