A chemist adds 190.0mL of a 1.90M nickel(II) chloride NiCl2 solution to a reaction flask. Calculate the millimoles of nickel(II) chloride the chemist has added to the flask. Round your answer to 3 significant digits.

361.0 milimoles of nickel chloride

Explanation:

Mili is a unit prefix that represents 1/1000 of the measured value. The multiplication of molarity with volume in liters gives the moles:

190.0mL = 0.190L * (1.90 moles / L) = 0.361 moles -Are moles of NiCl2.

Now, to convert moles to milimoles you must use 1 mole = 1000 milimoles thus:

0.361 moles * (1000 milimoles / 1 mole) =

it's c (engineer's do their work with mechanical stuff not on any living being)

i believe the answer is three water molecules