If Na was to form a 2 ion, from what orbital subshell would the second electron be lost?

2p

Explanation:

Sodium has an atomic number of 11, thus, the neutral atom has 11 electrons. The electron configuration is:

Na: 1s² 2s² 2p⁶ 3s¹

To gain stability, it loses an electron from its outer shell to form the cation Na⁺. Its electron configuration is:

Na⁺: 1s² 2s² 2p⁶

If it were to lose a second electron to form a Na²⁺ cation, the electron should be lost from the 2p orbital subshell and its electron configuration would be:

Na²⁺: 1s² 2s² 2p⁵

the answer is the

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation: