The decomposition of ethylene oxide(CH₂)₂O(g) → CH₄(g) + CO(g)is a first order reaction with a half-life of 58.0 min at 652 K. The activation energy of the reaction is 218 kJ/mol. Calculate the half-life at 629 K.

Half-life at 629K = 252.4min

Explanation:

Using Arrhenius equation:

And as Half-life in a first order reaction is:

We can convert the half-life of 58.0min to know K₁ adn replacing in Arrhenius equation find half-life at 629K:

K = 0.01195min⁻¹ = K₁

K₂ = 2.75x10⁻³ min⁻¹

And, replacing again in Half-life expression:

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