What is the concentration of MgSO4 in a solution prepared by dissolving 30g MgSO4 in 500ml distilled water. Express concentration in (i)ppm
(ii) %w/v
(iii) %w/w
Assume the solution density is 1.15g/ml.

Explanation:

Given:

Mass of solute = 30 gram

Volume of water = 500 ml

Density = 1.15g/ml

Find:

(i)ppm

(ii) %w/v

(iii) %w/w

Computation:

Water in gram = 500 ml × 1.15 g/ml

Water in gram = 575 gram

In ppm

Concentration of MgSO4 = [30 / 575] × 10⁶

Concentration of MgSO4 = 0.0521 × 10⁶ ppm

in % w/v

Concentration of MgSO4 = [30 / 500] × 100

Concentration of MgSO4 = 6% w/v

in % w/w

Concentration of MgSO4 = [30 / 575] × 100

Concentration of MgSO4 = 5.21% w/w

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.