the pain reliever codeine is a weak base with a kb equal to 1.6 x 10^-6. what is the ph of a 0.05 m aqueous codeine solution

Explanation:

Hello,

In this case, for the dissociation of the given base, we have:

Whereas CA accounts for conjugated acid and OH⁻ for the conjugated base. In such a way, equilibrium expression is:

And in terms of the reaction extent we can write:

For which the roots are:

For which clearly the result is the positive root which also equals the concentration of hydroxyl ions and we can compute the pOH:

And the pH:

Regards.

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