If the molarity of sugar is 1.1, what will the freezing point be?

The freezing point will be -2.046°C.

Explanation:

The freezing point depression equation is

Where;

= The temperature depression of the freezing point

= The constant of freezing point depression which is solvent dependent = 1.86°C/m

i = The number of particles the substance decomposes into in solution = 1 for sugar (a covalent compound)

m = The molality of the solution = 1.1

Therefore, we have;

Therefore the freezing point will be 0 - 2.046°C = -2.046°C.

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water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.