What is (oh-) in a solution of 0.125m ch3nh2 and 0.130m ch3nh3cl? Ka = 4.4×10^-4

Explanation:

The solution which contains 0.125 M CH3NH2 and 0.130 M CH3NH3Cl acts as buffer solution and the pOH of the buffer solution use the following Henderson-

Hasselbalch equation:

pOH = pKo + log(BH+)/[B]

Given that

CH3NH2 (aq) + H2O(l) + CH3NH, (aq) + OH- (aq)

Ky = 4.4 x 10-4

Here, the value of Ky

=- 4.4 x 10-4 ,Therefore pK is 3

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

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