The value of ΔH° for the reaction below is -126 kJ. The amount of heat that is released by the reaction of 30.0 g of Na2O2 with water is kJ. 2Na2O2 (s) + 2H2O (l) → 4NaOH (s) + O2 (g) A -126 B 24.2 C 67.5 D 48.4 E 96.9

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explanation:

your answer would be “dry”

the answer is 0.8m.

by: nicholas

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole