Sodium oxide has the chemical formula Na2O. What is the oxidation number of oxygen in this compound? Provide your answer below: ___

The oxidation number of oxygen in this compound is -2.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

In , sodium is having an oxidation state of +1 called as cation and oxygen is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"