If 35.2 g of magnesium react with excess hydrochloric acid, how many grams of magnesium chloride are produced? Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(aq)

139.33 g of magnesium chloride, MgCl2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(aq)

Next, we shall determine the mass of Mg that reacted and the mass of MgCl2 from the balanced equation.

This is illustrated below:

Molar mass of Mg = 24 g/mol

Mass of Mg from the balanced equation = 1 x 24 = 24 g

Molar mass of MgCl2 = 24 + (2x35.5) = 95 g/mol

Mass of MgCl2 from the balanced equation = 1 x 95 = 95 g

From the balanced equation above,

24 g of Mg reacted to produce 95 g of MgCl2.

Finally, we shall determine the mass of MgCl2 produced by reacting 35.2 g of Mg.

This can be obtained as follow:

From the balanced equation above,

24 g of Mg reacted to produce 95 g of MgCl2.

Therefore, 35.2 g of Mg will react to produce = (35.2 x 95)/24 = 139.33 g of MgCl2.

From the calculations made above, 139.33 g of magnesium chloride, MgCl2 were produced.

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