Calculate K c for the reaction 2HI(g) H 2(g) + I 2(g) given that the concentrations of each species at equilibrium are as follows: [HI] = 0.85 mol/L, [I 2] = 0.60 mol/L, [H 2] = 0.27 mol/L.

It will fall off and tip over. 

The answer is d.potassium

What’s the solution?

Answerδh > 0explanationc₆h₆  (s)  → c₆h₆ (l)if you are changing it from a solid to a liquid, you are pretty much melting the solid. this requires heat energy. therefore, the reaction is endothermic (takes in energy); the system enthalpy increases as the reaction proceeds: δh > 0.