Write electron configurations for the following ions. a. Ru^3+
b. As^3−
c. Y^3+
d. Pd^2+

Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. For example, [He]2s22p2 should be entered as [He]2s^22p^2.

Explanation:

Ions typically have different electron configurations compared to the parent atoms. This is due to the difference in the number of electrons depending on whether it is an anion (more electrons) or cation (less electrons).

a)Ru^3+

The electron configuration of Rubidium is; [Kr] 4d⁷ 5s¹

But Ru^3+ has 3 electrons lesser and would have the same electron configuration as Niobium.

The electron configuration is [Kr] 4d⁴ 5s¹

b)As^3−

The electron configuration of Arsenic is; [Ar] 3d¹⁰ 4s² 4p³

But As^3− has 3 electrons more and would have the same electron configuration as Krypton.

The electron configuration is [Ar] 3d¹⁰ 4s² 4p⁶

c) Y^3+

The electron configuration of Yttrium is; [Kr] 4d¹ 5s²

But Y^3+ has 3 electrons less and would have the same electron configuration as Krypton.

The electron configuration is [Ar] 3d¹⁰ 4s² 4p⁶

d) Pd^2+

The electron configuration of Palladium is; [Kr] 4d¹⁰

But Pd^2+ has 2 electrons less and would have the same electron configuration as Ruthenium.

The electron configuration is [Kr] 4d⁷ 5s¹

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