A study of the following system, 4 NH3(g) + 7 O2(g) <--> 2 N2O4(g) + 6 H2O(g), was carried out. A system was prepared with [N2O4] = [H2O] = 3.60 M as the only components initially. At equi­librium, [H2O] is 0.600 M. Calculate the equilibrium concentration of O2(g).

3.50 M

Explanation:

Step 1: Write the balanced equation

4 NH₃(g) + 7 O₂(g) ⇄ 2 N₂O₄(g) + 6 H₂O(g)

Step 2: Make an ICE chart

        4 NH₃(g) + 7 O₂(g) ⇄ 2 N₂O₄(g) + 6 H₂O(g)

I              0               0              3.60            3.60

C         +4x            +7x               -2x             -6x

E            4x              7x           3.60-2x      3.60-6x

Step 3: Calculate the value of x

The concentration of water at equilibrium is 0.600 M. Then,

3.60-6x = 0.600 M

x = 0.500 M

Step 4: Calculate the concentration of O₂ at equilibrium

The concentration of O₂ at equilibrium is 7x = 7(0.500M) = 3.50 M

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.

the correct answer would be b) volume versus temperature, because they are also directly proportional.