After 273 m3 of ethylene oxide at 748 kPa and 525 K is cooled to 293 K, it is allowed to expand to 1100. m3. The new pressure is kPa

Explanation:

To solve this problem, we can use the Combined Gas Laws:

Data:

p₁ = 748 kPa;  V₁ =   273 m³;  n₁ = n₁;  T₁ =  525 K

p₂ = ?;             V₂ = 1100. m³; n₂ =  n₁; T₂ =  293 K

Calculations:

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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