What is the pressure in millimeters of mercury of 0.0150 mol of helium gas with a volume of 213 mL at 50. C? (Hint: You must convert each quantity into the correct units (L, atm, mol and K) before substituting into the ideal gas law.)

Explanation:

0.08206 L atm mol-1K-1

pv=nRT

Px213 x10^-³ = 0.0150 x 0.08206 x 323

px213 x10^-³ = 0.398

p = 0.398/213 x10^-³

p = 1.87 x 10^-6atm

p = 0.0014mmHg

please brainliest

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

the answer is minerals.