if 140cm3 of methane diffuse into air in 72 sec, how long will it take 210cm3 of sulphur dioxide to diffuse under the same condition ?

time for sulphur dioxide to diffuse is 221.05 secs

gravity causes stares to cluster i think so

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm