If 56 J of heat is added to an aluminum can with a mass of 23.6 g , what is its temperature change? Specific heat capacity of aluminum is 0.903 J/g∘C.

Q = mass x sph x temp change

temp change = Q/(mass x sph)

Temp change =57/(22 x .903)

Temp Change = 2.97 ∘C

Temp change 3.0 ∘C

or

We can use the heat equation,

Q = mcΔT

Where Q is the amount of energy transferred (J), m is the mass of the substance (g), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

The given data

 Q = 52 J

 m = 28.4 g

  c = 0.903 J g⁻¹ °C⁻¹

ΔT = ?

By applying the formula,

 52 J = 28.4 g x 0.903 J g⁻¹ °C⁻¹ x ΔT

   ΔT = 2.03 °C

Hence, the temperature change of aluminium during the heating process is 2.03 °C.

what are the two models

explanation:

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