The balanced chemical equation for the reaction between sodium chloride and silver nitrate is: NaCl(aq) AgNO3(aq) AgCl(s) NaNO3(aq) We can interpret this to mean: ... 1 mole of sodium chloride and moles of silver nitrate React to produce ... moles of silver chloride and moles of sodium nitrate

1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃

Explanation:

The given reaction is a double decomposition (metathesis) reaction. A reaction in which the products are formed by the exchange of the ions present in the two reactants. NaCL and AgNO₃ exchange ions to form AgCl, which precipitates and NaNO₃.

The balanced equation for reaction is given below;

NaCl(aq) + AgNO₃(aq) > AgCl(s) + NaNO₃(aq)

In the reaction above, the mole ratio of the reactants to products is 1 : 1 ---> 1 : 1

This means that 1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃.

Given the molar mass of the compounds above;

NaCl = 58.5 g/mol; AgNO₃ = 170 g/mol; AgCl = 143.5 g/mol; NaNO₃ = 85 g/mol

Therefore, 58.5 g of NaCl reacts with 170 g of AgNO₃ to produce 143.5 g of AgCl and 85 g of NaNO₃

the answer to your question is c