A 0.750M solution of H2SO4 in water has a density of 1.046g/mL at 20°C. What is the concentration of this solution in molality g

0.717m

Explanation:

Molality, m, is an unit of concentration defined as the ratio between moles of solute and kg of solvent:

Molality: Moles solute / kg solvent.

In the problem, water is the solvent (Is the compound in the higher quantity) whereas H₂SO₄ is the solute.

The concentration of the solution is 0.750 moles H₂SO₄ / L.

Thus, you need to convert the liters to kg to obtain the molality. That is:

0.750 moles H₂SO₄ / L ₓ (1L / 1000mL) ₓ (1mL / 1.046g) ₓ (1000g / 1kg) =

0.717 moles H₂SO₄ / kg

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.

the answer would be b i believe