an extra strength antacid tablet contains 750 mg of active ingredient, caco3. if it takes 22.25 ml of hcl to neutralize the tablet, how strong is the acid

The HCl is very strong since its pH is equal to 0.17.

Explanation:

The reaction between CaCO₃ and HCl is:

CaCO₃(s) + 2HCl(aq) ⇄ CaCl₂(aq) + CO₂(g) + H₂O(l)     (1)    

The number of moles of CaCO₃ is:

Where:

m: is the mass = 0.750 g

M: is the molar mass = 100.0869 g/mol

From the reaction (1) we have that 1 mol of CaCO₃ reacts with 2 moles of HCl, so the number of moles of HCl is:  

Now, with the number of moles of HCl we can find its concentration:

Finally, the pH of the acid is:

The pH obtained is very low, so the HCl is very strong.

Therefore, the HCl is very strong since its pH is equal to 0.17.

I hope it helps you!  

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a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o