Which of the following electron configurations is incorrect? A) S [Ne]3s³3p⁴ B) Sn [Kr]5s²4d¹⁰5p² C) Rb [Kr]5s¹ D) V [Ar]4s²3d³ E) I [Kr]5s²4d¹⁰5p⁵

A S [Ne]3s³3p⁴ instead of [Ne]3s²3p⁴

Explanation:

Hello,

To find the incorrect electronics configuration, we have to refer back to our periodic table or simply writing the electronic configuration of each element down follow principles guiding it such as Aufbau principle and Hund's rule.

a) S = [Ne] 3s³ 3p⁴ instead of [Ne] 3s²3p⁴

Option A is wrong.

S orbital can only accommodate a maximum of 2 electrons and in this case, 3s orbital is carrying 3 electrons. This has violated the rule.

b) Sn = [Kr] 5s² 4d¹⁰ 5p²

Option B is correct

c) Rb = [Kr] 5s¹

Option c is correct

d) V = 4s² 3d³

Option D is correct

e) I = [Kr] 5s² 4d¹⁰ 5p⁵

From the above, we can see that the answer is option A = S

the answer is definitely c.

the answer is barium and copper bromide