Hi does anyone know how to do question 4?
Please show working out thanks.

a)1.274 g b) 0.013 mole

Explanation:

a) Mass of 1 mol of CuSo4. 5H20=

=246g

no. moles of CuSo4. 5H2O=

so moles

=

0.013 mole

in the equation

1 mole of sulphuric acid reacts to form 1 mole of CuSo4.5H2O

in other words

0.013 mole of sulphuric acid reacts to form 0.013 mole of CuSo4.5H2O

so mass of 1 mole (Mr) H2So4=

98g

mass of sulphuric acid= mole × mass of 1 mole

so mass= 0.013 × 98

1.274 g

b) In the equation

1 mole of sulphuric acid reacts to form 1 mole of copper(ll) oxide

in other words

0.013 mole of sulphuric acid reacts to form 0.013 mole of copper (ll) oxide

so 0.013 mole of copper(ll) oxide is reacted

Hope it helped and pls mark brainliest