g what mass of water must evaporate from the skin of a 70.0 kg man to cool his body 1.00 C? The heat of vaporization of water at body temp

The correct answer will be "100.7 mL". The further explanation is given below.

Explanation:

The given values are:

Temperature,

ΔT = 1°C

Mass,

m = 70 kg

c = 3.480 J/Kg.K

Amount of released heat will be:

⇒  

On putting the estimated values, we get

Let M will be the amount of evaporated water at the temperature of 37°C.

Required heat will be:

⇒  

Now, Lost heat will be equal to the required amount of heat.

⇒                          

On applying cross-multiplication, we get

Now,

⇒  

On putting the estimated values, we get

im not exactly sure but i think its b!