Label the following reactions as oxidation or reduction. Cr+3(aq) + 3e-s → Cr Ag(s) → 1e-s + Ag+1(ag) Mn(s) → 5e-s + Mn+5(aq) Sn+2(aq) + 2e-s → Sn

See the explanation

Explanation:

Our reactions for this question are:

a) Cr+3(aq) + 3e- → Cr(s)

b) Ag(s) → 1e- + Ag+1(ag)

c) Mn(s) → 5e- + Mn+5(aq)

d) Sn+2(aq) + 2e- → Sn(s)

Now, we have to remember the definition of oxidation and reduction. In a reduction reaction,  the substance will gain electrons, in other words: "The electrons would be placed on the left side, in the side of the reagents. In an oxidation reaction, the substance will lose electrons, in other words: "The electrons would be placed on the right side, in the side of the products".

With this in mind we will have:

a) Cr+3(aq) + 3e- → Cr (s)(Reduction)

b) Ag(s) → 1e- + Ag+1(ag) (Oxidation)

c) Mn(s) → 5e- + Mn+5(aq) (Oxidation)

d) Sn+2(aq) + 2e- → Sn(s) (Reduction)

I hope it helps!

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current

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