Write the empirical formula of the compound with the following composition. 63.15% C
5.30% H
31.55% O

C₈H₈O₃  

Explanation:

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of C:H:O.

Assume 100 g of the compound.

1. Calculate the mass of each element.

Then we have 63.15 g C, 5.30 g H, and 31.55 g O.

2. Calculate the moles of each element

3. Calculate the molar ratio of the elements

Divide each number by the smallest number of moles

C:H:O = 5.258:5.258:1.972 = 2.667:2.666:1

4. Multiply by a number to make each ratio close to an integer

Multiply the ratios by three.

2.667:2.666:1 = 8.000:8.000:3 ≈ 8:8:3

5. Write the empirical formula

EF = C₈H₈O₃

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