What is the mass in grams of each elemental sample? A. 6.65 mol W
B. 0.588 mol Ba
C. 68.4 mil Xe
D. 1.57 mol S

Mass (m) = Number of moles(n) × Molar mass (M)

A. 6.65 mol W

M (W) = 184 g/mol

n = 6.65mol

mass of W = 6.65 × 184 = 1223.6g

B. 0.588 mol Ba

M(Ba) = 137g/mol

n = 0.588 mol

mass of Ba = 0.588 × 137 = 80.556g

C. 68.4 mol Xe

M(Xe) = 131g/mol

n = 68.4 mol

mass of Xe = 68.4 × 131 = 8960.4g

D. 1.57 mol S

M(S) = 32.1 g/mol

n= 1.57 mol

mass of S = 1.57 × 32.1 = 50.397g

Hope this helps

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied