Consider the reaction: 2N2(g) + O2(g)2N2O(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.65 moles of N2(g) react at standard conditions. S°system = J/K

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

the answer is na (sodium)

explanation:

i think its 100

i hope this !