What are the coeffients that balance the following skeletal equation?
CH4 + O2 + Cl2 ® HCI + CO

CH4 ---> 2

CL2 > 4

HCL > 8

CO> 2

Explanation:

Equation

CH4 + O2 + Cl2 => HCI + CO

we have to balance it

On LHS  atoms of oxygen is 2  while on RHS it is 1 atom so lets balance oxygen  first

to balance oxygen on RHS we add 2 as coefficient to CO

CH4 + O2 + Cl2 => HCI + 2CO

On RHS  atoms of Carbon is 2  while on RHS it is 1 atom so lets balance Carbon   now

to balance Carbon on LHS we add 2 as coefficient to CH4

2CH4 + O2 + Cl2 => HCI + 2CO

On LHS atoms of hydrogen is 8 so lets balance hydrogen now

to balance hydrogen on RHS we add 8 as coefficient to HCL

2CH4 + O2 + Cl2 => 8HCI + 2CO

On RHS atoms of Cl is 8 while on LHS  atoms of Cl is 2.

To make no of atoms of Cl 8 on LHS we add 4 as coefficient

2CH4 + O2 + 4Cl2 => 8HCI + 2CO

Thus, coefficients are as given below

CH4 ---> 2

CL2 > 4

HCL > 8

CO> 2

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