calculate how many moles of CaCl2•2H2O are present in 1.50 g of CaCl2•2H2O and then calculate how many moles of pure CaCl2 are present in the 1.50 g of CaCl2•2H2O.

Explanation:

For this question, we have to start with the molar mass calculation of . For this, we have to know the atomic mass of each atom:

O: 16 g/mol

Cl: 35.45 g/mol

H: 1 g/mol

Ca: 40 g/mol

If we take into account the amount of each atom in the formula we will have:

So, in 1 mol of we will have 147.01 g. Now we can do the conversion:

Additionally, in 1 mol of we will have 1 mol of . Therefore, we have a 1:1 mol ratio . With this in mind, we will have the same number of moles for

I hope it helps!

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