Cuál es el radio atómico de una molécula diatómica si su diámetro es de 2,28 angstroms?

1.14 angstroms

Explanation:

Matemáticamente, el radio atómico de una molécula diatómica se define como la mitad del diámetro de la molécula diatómica.

Esto significa que para obtener el valor del radio atómico de la molécula diatómica, necesitamos dividir el diámetro de la molécula diatómica entre 2 En esta pregunta, lo que haremos es dividir el diámetro dado en la pregunta por 2 Por lo tanto,

el radio atómico será 2.28 angstroms / 2 = 1.14 angstroms Entonces, el radio atómico de la molécula diatómica es 1.14 angstroms

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: