The H 2 produced in a chemical reaction is collected through water in a eudiometer. If the pressure in the eudiometer is 760.0 torr and the vapor pressure of water under the experimental conditions is 23.8 torr, what is the pressure (torr) of the H 2 gas

the pressure (torr) of theH₂ gas is 736.2 torr

Explanation:

Given that

The H₂ gas  produced in a chemical reaction is collected through water in a eudiometer; during this process, the gas collected contains some droplets of water vapor along with these gas.

So; the total pressure in the eudiometer = Pressure in the H₂ gas  - Pressure of the water vapor

Where;

=  total pressure in the eudiometer = 760.0 torr

= Pressure in the H₂ gas  = ???

= Pressure in the water vapor  = 23.8 torr

Now:

= +

- = + -

 = - +

 =  (- 23.8 + 760) torr

 = 736.2 torr

Thus; the pressure (torr) of theH₂ gas is 736.2 torr

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.