How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution?

700 mL of water

Explanation:

This is the perfect example of dilation calculations. Along with this concept we have a formula c = n ( solute ) / V ( solution ). Let us first solve for n by changing this equation to isolate the solute,

n ( KCL ) = 2.4 mol / L * 500 * 10 ^ - 3 L,

n ( KCL ) = 1.2 moles ( KCL )

Knowing the amount of moles of potassium chloride, we have to now identify how much is present in the target solution,

V = 1 .2 moles /  ( 1.0 moles / L )

V = 1.2 L = 1200 mL

Vadded = 1200 - 500 = 700 mL

Hope that helps!

Use dilution equation:

M1V1 =

M2V2 1.0*V1 =

2.4*500 V1 =

1200mL

You already have 500mL KCl solution . You must add: 1200mL - 500mL = 700mL water.

Explanation:

Hope this helps!!! <3

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

the answer would be b i believe