An excess of sodium carbonate, Na2CO3, in solution is added to a solution containing 15.71 g CaCl2. After performing the experiment, 13.19 g of calcium carbonate, CaCO3, is produced. Calculate the percent yield of this reaction

93.15 %

Explanation:

We have to start with the chemical reaction:

Now, we can balance the reaction:

Our initial data are the 15.71 g of , so we have to do the following steps:

1) Convert from grams to moles of using the molar mass (110.98 g/mol).

2) Convert from moles of to moles of using the molar ratio. ( 1 mol = 1 mol of ).

3) Convert from moles of to grams of using the molar mass. (100 g/mol).

Finally, we can calculate the yield percent:

I hope it helps!

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