Chemistry, 25.06.2020 03:01 jsh65bsbs

Four landing sites are proposed for a lander. Data about the sites are listed in the table.
At which landing site would the lander have the greatest
amount of gravitational potential energy?
Landing Site
w
W
х
Y
Z
Height above
Surface (m)
32
16
35
Acceleration Due to
Gravity (m/s)
1.6
3.7
1.6
3.7
ОХ
OY
12
N

Answers: 1

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Answers

Gravitational energy is the power stored in an object due to the intensity of gravity or because the article is located vertically.

The correct answer is:

The site at which the lander would have the greatest amount of gravitational potential energy is X.

The correct explanation for site X is:

The gravitational energy can be calculated as the product of mass, gravitational field and height.

${\text{PE}_{\text G}&= \text{m}\; \times\text g\times \Delta\text H$

Where,

g = acceleration due to gravitym = massh = height

Given,

Landing site Height above surface Gravity

W 32 1.6

X 16 3.7

Y 35 1.6

Z 12 3.7

We can calculate Gravitational energy for all the sites as follows:

Site W:

${\text{PE}_{\text G}&= \text{m}\; \times\ 1.6\times 32 = 51.2 \text \; \times \text {m}$

Site X:

${\text{PE}_{\text G}&= \text{m}\; \times\ 3.7\times 16 = 59.2 \text \; \times \text {m}$

Site Y:

${\text{PE}_{\text G}&= \text{m}\; \times\ 1.6\times 35 = 56 \text \; \times \text {m}$

Site Z:

${\text{PE}_{\text G}&= \text{m}\; \times\ 3.7 \times 12= 44.4 \text \; \times \text {m}$

Therefore, the greatest amount of gravitational energy 59.2m is present on-site X.

To learn more about gravitational potential energy follow the given link:

link

Answer from: Babybeast3544

The site at which the lander would have the greatest amount of gravitational potential energy is X

Explanation:

The formula for gravitational potential is given as follows;

$PE_G = m \times g \times \Delta H$

Where:

g = Acceleration due to gravity

m = Mass of the lander

ΔH = Height above surface

Landing site --- Height above surface --- Acceleration due to gravity

W 32 1.6

x 16 3.7

Y 35 1.6

Z 12 3.7

Therefore, we have;

For site W

$PE_G = m \times 1.6 \times 32 = 51.2 \cdot m$

For site X

$PE_G = m \times 3.7 \times 16= 59.2 \cdot m$

For site Y

$PE_G = m \times 1.6 \times 35 = 56 \cdot m$

For site Z

$PE_G = m \times 3.7 \times 12 = 44.4 \cdot m$

Hence the site at which the lander would have the greatest amount of gravitational potential energy is X with PE_G = 59.2·m.

Answer from: Quest

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Answer from: Quest

B. a graduated substance

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