What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is 3.611 × 10-15 joules? (Planck's constant is 6.626 × 10-34 joule seconds)

5.449 x 10¹⁸ Hz

Explanation:

Energy (E) =Frequency (F) x Plancks constant (h)

F= 3.611x10⁻¹⁵J / 6.626 x 10⁻³⁴ Js⁻¹

F =5.449 x10¹⁸ s⁻¹ or 5.449 x 10¹⁸ Hz

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.