Chemistry, 23.06.2020 10:57 oof4457

Iwi ance the following chemical equation:
NaBr -
C1
NaCl
Bro
ick? Watch a video or use a hint.

Answers: 2

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Answer from: Fiwui

2NaBr + Cl₂ ⟶ 2NaCl + Br₂

Explanation:

NaBr + Cl₂ ⟶ NaCl + Br₂

1. Put a 1 in front of the most complicated-looking formula (Br₂?):

NaBr + Cl₂ ⟶ NaCl + 1Br₂

2. Balance Br:

We have fixed 2 Br on the right. We need 2 Br on the right. Put a 2 in front of NaBr to fix it.

2NaBr + Cl₂ ⟶ NaCl + 1Br₂

3. Balance Na:

We have fixed 2 Na on the left. We need 2 Na on the right. Put a 2 in front of NaCl.

2NaBr + Cl₂ ⟶ 2NaCl + 1Br₂

4. Balance Cl

Done.

The equation should now be balanced.

5. Check that atoms balance:

$\begin{array}{ccc}\textbf{Atom} & \textbf{On the left} & \textbf{On the right}\\\text{Na} & 2 &2\\\text{Br} & 2 & 2\\\text{Cl} & 2 & 2\\\end{array}$

It checks.

The balanced equation is

2NaBr + Cl₂ ⟶ 2NaCl + Br₂

Answer from: Quest

dishwashers don't have rights

explanation:

dishwashers are meant for one thing and one thing only: dishwashing. they belong in the kitchen making sandwiches and cleaning up for the man of their household. if your dishwasher starts acting up just slap it and wait a minute.

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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Iwi ance the following chemical equation:
NaBr -
C1
NaCl
Bro
ick? Watch a...

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