Amaterial has a density of 8.9 g/cm^3. you have 3 grams of the substance. how much space does it take up? a. 0.3cm3 b. 3.0 cm3 c. 5.9 cm3 d. 27 g/cm3

Volume of the material is

Explanation:

It is given that,

Density of a material,

Mass of the material,

We need to find the volume occupied by the material. The formula for the density is given by :

So, the space occupied by the material is . Hence, this is the required solution.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :