To raise the temperature of 166.3 g of water from 50.00 °C to 60.00 °C requires how much heat?

6951 J

Explanation:

For this problem, we would use the equation for heat to find the amount of heat required.

q=mCΔT

We are given our mass and temperature, but we need the specific heat of water which is C=4.18J/g°C

q=(166.3g)(4.18J/g°C)(60.00-50.00°C)

q=6951J

Question:

To raise the temperature of 166.3 g of water from 50.00 °C to 60.00 °C requires how much heat?

Specific heat of water =4.2 J/g C ( approx )

Q=mC∆T

Now put the values

Q=166.3× 4.2( 60-50)

= 166.3× 4.2× 10

= 166.3× 42

= 6984.6 J

Hope it's help you.