The pressure on 30 milliliter of an ideal gas increases from 101.3 kPa to 202.6 kPa at constant temperature. What is the new volume?

The new volume is 0.015 L

Explanation:

Boyle's Law is a gas law that relates the pressure and volume of a certain amount of gas, without temperature variation, that is, at constant temperature.

Boyle's law says:

"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure"

That is to say that if the pressure increases, the volume decreases and if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or P * V = k

If a change in pressure or volume occurs at a constant temperature, the following is true:

P1*V1 = P2*V2

Where P1 and V1 are the pressure and volume in state 1 and P2 and V2 are the pressure and volume in state 2.

That is, the product between the initial pressure and the initial volume is equal to the product of the final pressure times the final volume.

In this case:

P1= 101.3 kPa=101,300 Pa (being 1 kPa=1,000 Pa)V1= 30 mL= 0.03 L (1 L= 1,000 mL)P2= 202.6 kPa=202,600 Pa V2= ?

Replacing:

101,300 Pa*0.03 L=202,600 Pa* V2

Solving:

V2= 0.015 L

The new volume is 0.015 L

Idid the calculation and i get 875,000,000 which can be written as 8.75 x 10^6?

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