An enzyme can catalyze a reaction with either of two substrates, S1 or S2. The Km for S1 was found to be 2.0 mM, and the Km, for S2 was found to be 20 mM. A student determined that the Vmax was the same for the two substrates. Unfortunately, he lost the page of his notebook and needed to know the value of Vmax. He carried out two reactions: one with 0.1 mM S1, the other with 0.1 mM S2. Unfortunately, he forgot to label which reaction tube contained which substrate. Determine the value of Vmax from the results he obtained:

101

Explanation:

Provided that

And,

Now we expect the same

{S} (0.1mM)

This determines that generates a  higher rate of product formation as compared to the

So we can easily calculate the for either of or as we know that Tube 1 is and tube 2 is

As we know that

As the rates do not include any kind of units so we do not consider the units for

Now the calculation is

= 100.5

≈ 101

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.

c. orbital shape i hope this is correct