How many grams of sodium nitrate are needed to make 2.50L of 1.12m solution

 238 g of sodium nitrate are needed to make 2.50L of 1.12m solution

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,

n = moles of solute

= volume of solution in L

Now put all the given values in the formula of molality, we get

moles of = 2.8

moles of

Thus 238 g of sodium nitrate are needed to make 2.50L of 1.12m solution

bcde is the incorrect answer it is a

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8