Compound A (C9H12) shows prominent peaks in its mass spectrum at m/z 120 and 91. Compound B (also C9H12) shows prominent peaks at m/z 120 and 105. On vigorous oxidation with chromic acid, both compounds give benzoic acid. From this information, deduce the structures of both compounds.

Compound A: Propylbenzene

Compound B: Cumene

Explanation:

On this case, we have two clues:

1) The mass spectrometry info

2) The formation of benzoic acid

If we have the formation of benzoic acid with a strong oxidant (). It means that we have an alky group bonded to benzene. Therefore we have to add three carbons to a benzene ring in order to obtain the mass of the compound (120).

The next question is how these three additional carbons are bonded to the benzene. For this, we have to check the mass info. For compound A we have a fragmentation moeity on 91 therefore we have a loss of an ethyl group. Therefore compound A have a linear structure for the aditional three carbons.

For compound B we have a fragmentation moeity on 105 this means a loss of 15 units of mass therefore we loss a methyl group. This indicates that we have a non linear structure fo the three additional carbons.

See figures 1 and 2.

I hope it helps!

icc, international association for cereal chemistry

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