How many moles of phosphoric acid are required to neutralize 7.2 mol of potassium hydroxide?

2.4 Moles of Phosphoric acid are required to neutralize 7.2 moles of potassium hydroxide

Explanation:

Phosphoric acid =  Formula: H3PO4

Potassium hydroxide = Formula: KOH

H3PO4 + 3KOH = K3PO4 + 3H2O

Ratio 1:3

7.2 mol Potassium hydroxide = Formula: KOH

7.2/3 = 2.4 Mol Phosphoric acid =  Formula: H3PO4

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.