Help PLEASE ill give Brainiest Calculate the percent ionic character of a chemical bond between strontium and chlorine.

67 percent
33 percent
70 percent
30 percent

10.063g / 10.00 ml = 1.0063 g/ml which rounds off to 4 sig figs as: 1.006 g/ml

(no3)⁻n has oxidation number x,o has oxidation number -2.(x*1 -2*3) charge of the nitrate ion, and we know that charge of the nitrate ion =-1.so,(x*1 -2*3) =-1x-6=-1x=+5answer a. +5.