What is the final volume of a gas that started at 20 L and 50 atm pressure when the pressure is decreased to 14 atm? Answer must be to nearest whole number.

Final volume = 71 L

Explanation:

Since the question involves volume and pressure, we use Boyle's law which states that

P1V1 = P2V2;

Where P1 and P2 are initial and final pressure respectively, and V1 and V2 are initial and final volumes respectively.

P1 =50 atm, P2 = 14 atm, V1 = 20 L, V2 = ?

V2 = P1V1/P2

V2 = (50 * 20)/14

V2 = 71 L

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

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