Be sure to answer all parts. Metal hydrides react with water to form hydrogen gas and metal hydroxide. For example, SrH2(s) + 2H2O(l) → Sr(OH)2(s) + 2H2(g) You wish to calculate the mass of hydrogen gas that can be prepared from 5.64 g of SrH2 and 4.70 g of H2O. (a) How many moles of H2 can be produced from the given mass of SrH2?

Explanation:

SrH₂ + 2H₂O = Sr(OH)₂ + 2H₂

90gm     36gm                  2 moles

5.64 g        4.7 g

water required for 5.64 g of SrH₂ = (36/ 90) x 5.64 g

= 2.256 g

water is in excess . Hence limiting reagent is SrH₂

90g SrH₂  makes 2 mole of water

5.64g SrH₂ makes water equal to mole = 2 x 5.64 / 90

= .125 mole .

mole of hydrogen formed = .125 .

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year